69:Tb4e,

S=\pi\displaystyle\int_1^2(2x+1)^2\,\mathrm{d}x

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S=\displaystyle\int_1^2(2x+1)\,\mathrm{d}x

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S=\pi\displaystyle\int_1^2(2x+1)\,\mathrm{d}x

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S=\displaystyle\int_1^2(2x+1)\,\mathrm{d}x

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Câu 2 Phần I · Đề chính thức Toán 2025 (Bộ GD&ĐT) – mã đề 0104